Suppose that the position of a particle is given by $s = f(t) = 3t^2 + 4t + 9$. (a) Find the velocity at time $t$. v(t) = \frac{m}{s} (b) Find the velocity at time $t = 3$ seconds. \frac{m}{s} (c) Find the acceleration at time $t$. a(t) = \frac{m}{s^2} (d) Find the acceleration at time $t = 3$ seconds. \frac{m}{s^2}
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Step 1: Given that the velocity function is vt= 3t^2 - 6t + 5, we can find the velocity at time t by taking the derivative of the function with respect to t. Show more…
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