0:00
All right.
00:01
So if we have the overall set containing one, two, three, and four, we want four different subsets such that if we take the intersection of two subsets, they're all different.
00:14
So the intersection would be points in both of the sets.
00:20
So if we just put one element per set, we're told to label that may be c &d, then there would be the zero set for all the intersections.
00:28
So that's not valid.
00:30
What if we do? let's see, a has just one, b has one and two, c has one and three, well, no, then that would be the same.
00:54
Then a intersecting with c would just be one, and b intersecting with a would just be the number one, or the set containing one.
01:07
What if we do two and three? all right, then a and b have the intersection of the set 1, a and c have an intersection of 0, b and c have the intersection of 2.
01:22
So d has to be, well, what if d is, contains 1, 2, 3, and 4? then, oh, maybe if a also contains 4.
01:50
Let's see, then the intersection of a and b is the set 1, the intersection of a and c is 1 and 4...