A frictionless spring with a 7-kg mass can be held stretched 0.6 meters beyond its natural length by a force of 90 newtons. If the spring begins at its equilibrium position, but a push gives it an initial velocity of 2.5 m/sec, find the position of the mass after tt seconds.
Added by Jason P.
Step 1
The spring constant can be found using Hooke's law, which states that the force needed to extend or compress a spring by some distance is proportional to that distance. The formula for Hooke's law is F = kx, where F is the force, k is the spring constant, and x is Show more…
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