A gas has a volume of 48.5 L, a pressure of 0.500 atm, and a temperature of 325 K. If the pressure is raised to 1.20 atm and the temperature is lowered to 320 K, what is the final volume of the gas?
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The combined gas law equation is given by: (P1 * V1) / (T1) = (P2 * V2) / (T2) where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature. Show more…
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I have an unknown volume of gas at a pressure of 0.500 atm and a temperature of 325 K. If I raise the pressure to 1.20 atm, decrease the temperature to 320. K, and measure the final volume to be 48.0 liters, what was the initial volume of the gas?
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