For the quadratic function \(y = x^2 - 1\), we can start by finding the vertex. The vertex of a quadratic function in the form \(y = ax^2 + bx + c\) is given by the formula \(x = -\frac{b}{2a}\). In this case, \(a = 1\) and \(b = 0\), so the vertex is at \(x =
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