A hydraulic turbine has 85 m of elevation difference available at a flow rate of 0.25 m^3/s, and its overall turbine-generator efficiency is 91 percent. Determine the electric power output of this turbine.
Added by Alan P.
Step 1
Given: - Elevation difference (h) = 85 m - Flow rate (V_dot) = 0.25 m^3/s - Density of water (rho) = 1000 kg/m^3 - Acceleration due to gravity (g) = 9.81 m/s^2 Water power input (W_dot_turbine) = h * V_dot * rho * g W_dot_turbine = 85 * 0.25 * 1000 * Show more…
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