e. the temperature of its surroundings).
$$ \frac{dT}{dt} = k(T - T_a) $$
where $T$ is the temperature of the object at time $t$, $T_a$ is the ambient temperature, and $k$ is a constant.
In this case, $T_a = 0$. So,
$$ \frac{dT}{dt} = kT $$
$$ \int \frac{dT}{T} =
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