(a) \( \mathbf{m}=\left(\begin{array}{l}3 \\ 2\end{array}\right) \quad \mathbf{n}=\left(\begin{array}{r}-2 \\ 3\end{array}\right) \) (i) Work out \( 2 m-3 n \).
Added by Leslie E.
Close
Step 1
First, let's calculate \(2m\): \(2m = 2 \left(\begin{array}{l}3 \\ 2\end{array}\right) = \left(\begin{array}{l}2 \cdot 3 \\ 2 \cdot 2\end{array}\right) = \left(\begin{array}{l}6 \\ 4\end{array}\right)\). Show more…
Show all steps
Your feedback will help us improve your experience
Angela Guo and 91 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
$n_{1}=2$ $n_{2}=-3$
Rational Expressions and Equations
Solving Rational Equations
$$ \frac{m+3}{n-2}=\frac{4}{5} \text { for } n $$
Solve Rational Equations
Solve for n. $$\left(\begin{array}{l}n \\3\end{array}\right)=2 \cdot\left(\begin{array}{c}n-1 \\2\end{array}\right)$$
Sequences, Series, and Combinatorics
Combinatorics: Combinations
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD