Given:
Initial velocity, \(v_0 = 86.0 \, \text{m/s}\)
Range, \(R = 300 \, \text{m}\)
Angle, \(\theta = 11.7^\circ\)
Use the formula for range in projectile motion:
\[ R = \frac{v_0^2 \sin(2\theta)}{g} \]
where \(g = 9.81 \, \text{m/s}^2\) is the acceleration due
Show more…