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Hi.
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In this problem, we're given a probability matrix a, which is shown here.
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And a probability matrix is defined as a square matrix, such that each of the entries, the sum of the rows, equals 1.
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So you can see that that is the case here.
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So the first thing we want to do is show that the, that lambda equals 1 is an eigenvalue of a.
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So remember, an eigenvalue lambda, sat satisfies the eigenvalue lambda satisfies that the determinant of a minus lambda i is equal to zero.
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So if, uh, so if one is, uh, an eigen value, and this means that the determinant of a minus i should equal zero.
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So here we have, well, i wrote out a minus lambda i.
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And if you plug in, uh, lambda equals one here, um, you get point negative, or sorry, point negative five, negative, negative.
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0 .5, negative 0 .5, you get negative 0 .3, you get negative 0 .9.
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And then we calculate the determinant here.
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So we have negative 0 .5 times the determinant of this minus 0 .4 times the determinant of this, and so on.
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And this is just a calculation.
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So i'll assume you should be able to do it.
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But if you do this, you get this is the determinant.
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And if you plug it into your calculator, you do in fact get zero.
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I'm sorry, it's frozen a little bit...