00:01
In the mentioned question, we are given two circuits.
00:05
One is open circuit test, open circuit test and other one is the short circuit test.
00:21
Here we are given the voltage, current and power.
00:25
Voltage, current and the power.
00:32
Over here the voltage is 250 volts, current 1 .5 amperes and power is 100 watt.
00:43
Whereas in the short circuit we have 10 volt of voltage, 8 ampere of current and 320 watt of the power.
00:53
Now this thing is known as a low voltage side, low voltage side.
01:06
Whereas this one is known as high voltage side.
01:15
Because these two are measured at this one as low and this one as high.
01:19
Now we have to compute the parameters for equivalent circuit and we have to then draw the diagram of our equivalent circuit.
01:36
So for that we have the values like the cos of xi open circuit equals to power of open circuit by voltage of open circuit into the current of open circuit.
01:53
So it will be 100 upon 250 into 1 .5, the parameters from this open circuit.
02:02
So we will get xi open circuit equals to 0 .267.
02:10
Then we have on value equals to open circuit current into cos of xi0c.
02:21
Okay.
02:21
So here it will give us the value in amperes 0 .4 ampere.
02:27
Similarly open circuit's current will be equals to cos into sin xi0c that will be equals to 1 .445 ampere.
02:40
Now we have to calculate the shunt branch, shunt branch.
02:48
For that we have the value of rm and vm, sorry rm and xm.
02:53
Rm is calculated as v upon ic and xm is calculated as v upon our im.
03:02
So v over here is 250, ic is you can see 1 .445 here.
03:11
Similarly, in this v is 250 and this is 0 .4...