A small truck has a mass of 2175kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on a level road? Solve for work required to decrease speed in J.
Added by Ana B.
Step 1
0 m/s. The formula for kinetic energy is KE = 1/2 * m * v^2, where m is the mass and v is the velocity. So, the initial kinetic energy is KE_initial = 1/2 * 2175kg * (25.0 m/s)^2 = 680937.5 J. Show more…
Show all steps
Your feedback will help us improve your experience
Ankur S and 76 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A small truck has a mass of 2100 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 12.0 m/s on a level road?
Prabhu R.
You are testing a new amusement park roller coaster with an empty car of mass 120 kg. One part of the track is a vertical loop with radius 12.0 m. At the bottom of the loop (point $A$) the car has speed 25.0 m/s, and at the top of the loop (point $B$) it has speed 8.0 m/s. As the car rolls from point $A$ to point $B$, how much work is done by friction?
Potential Energy and Energy Conservation
Gravitational Potential Energy
A 1250-kg car moves at 20.0 m/s. How much work must be done on the car to increase its speed to 30.0 m/s?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD