A solid disk of mass M = 0.650 kg and radius R = 0.300 m is suspended vertically and is free to rotate about its center without friction. A point object that has the same mass as the disk is placed at an angle ????????????????????????????????????????????????????????????????????????????????????????????????????????????????_i = 15.0° clockwise from the top along the rim, causing the disk to rotate. The acceleration due to gravity is g = 9.80 m/s². What is the angular speed ?_f of the disk when the object is directly below the center of the disk. ?_f = rad/s
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First, we need to find the moment of inertia (I) of the disk. The moment of inertia of a solid disk is given by the formula: I = (1/2)MR^2 where M is the mass of the disk and R is its radius. Show more…
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