A solution is made by mixing 122.g of acetyl bromide CH3COBr and 129.g of heptane C7H16. Calculate the mole fraction of acetyl bromide in this solution. Be sure your answer has the correct number of significant digits.
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Given: Mass of acetyl bromide (CH3COBr) = 122.9 g Molar mass of acetyl bromide (CH3COBr) = 122.9 g/mol Number of moles of acetyl bromide = Mass / Molar mass Number of moles of acetyl bromide = 122.9 g / 122.9 g/mol Number of moles of acetyl bromide = 1 mol Show more…
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