Question

A solution is made by mixing 58. g of thiophene ($C_4H_4S$) and 71. g of benzene ($C_6H_6$). Calculate the mole fraction of thiophene in this solution. Round your answer to 2 significant digits.

          A solution is made by mixing 58. g of thiophene ($C_4H_4S$) and 71. g of benzene ($C_6H_6$).
Calculate the mole fraction of thiophene in this solution. Round your answer to 2 significant digits.

$A solution is made by mixing 58. g of thiophene (C4H4S) and 71. g of benzene (C6H6). Calculate the mole fraction of thiophene in this solution. Round your answer to 2 significant digits.$

Added by Elizabeth A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

08/20/2022

Step 1

Molar mass of thiophene (C4H4S): 4(12.01 g/mol) + 4(1.01 g/mol) + 1(32.07 g/mol) = 84.14 g/mol Molar mass of benzene (C6H6): 6(12.01 g/mol) + 6(1.01 g/mol) = 78.11 g/mol Show more…

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A solution is made by mixing 58. g of thiophene (C_(4)H_(4)(S)) and 71.g of benzene (C_(6)H_(6)). Calculate the mole fraction of thiophene in this solution. Round your answer to 2 significant digits. A solution is made by mixing 58. g of thiophene (C4H S) and 71. g of benzene (CgH) Calculate the mole fraction of thiophene in this solution. Round your answer to 2 significant digits