00:01
Hello, in this problem we have a car that is accelerating at 3 .2 meters per second.
00:10
So i'm going to say a is equal to 3 .2 meters per second.
00:18
I mean 3 .2 meters per second squared.
00:23
And we want to find, well, we have a timeline from 0 seconds to 5 .5 seconds.
00:33
And between 4 .5 seconds and 5 .5 seconds the car has traveled 35 meters so it's traveled 35 meters in one second because that's what you know we're going to call this t1 so time 1 and this t 2 and t0 right here equals 0 seconds so t 2 so t 2 minus t 1 is just 1 second.
01:13
So the car has traveled 35 meters in one second, which is also equivalent to the velocity being 35 meters per second.
01:28
Now we want to find the velocity at this exact time right here.
01:34
So what is v0? we actually, we don't know the velocity at this time point and we don't know the velocity at this time point, but we can easily find this velocity between these two time points, which is also saying that it's the average velocity between these time points, which is this velocity, 35 meters per second.
02:06
Now we know that the car is accelerating at 3 .2 meters per second square, which means that the velocity is increasing by 3 .2 per second.
02:21
So if you imagine the average velocity say is like, we'll say the average velocity is v1 plus v2, where we're going to have v1 be at time 1 at 4 .5 seconds, and v2 will be at 5 .5 seconds, which we don't know these velocities, but the average between them divided by 2 is equal to 35 meters per second.
03:05
Here if you recall we get this velocity right here by saying v equals t2 minus t1 divided by 35 meters, which is equal to 5 .5 seconds minus 4 .5 seconds divided by 35 meters.
03:45
So this must equal 35 meters per seconds, what we get for this.
03:51
So we could find v1, we could find v2.
03:58
Knowing that the car accelerates, knowing that the car, the velocity changes by 3 .2 every second, it increases by 3 .2 every second.
04:11
That means from v1 to v2, the velocity should have increased by 3 .2, since this time scale is just one second.
04:26
So we're going to just write that down right here, that v2 minus v1, which we're just saying that the difference in velocity from these two timescales, over the time, which is one second, is equal to the acceleration, which is 3 .2 meters per second squared...