a steel piano wire 40 cm long of mass 8 gm is stretched with a tension 200 n. i) what is its fundamental frequency? ii)what is the number of highest ovetone that could be heared by the person who is capable of hearing frequencies upto 20k hz
Added by Al Mahmud S.
Step 1
Given: Length of the wire, L = 40 cm = 0.4 m Mass of the wire, m = 8 g = 0.008 kg Tension, T = 200 N Calculate the mass per unit length: μ = m / L = 0.008 kg / 0.4 m = 0.02 kg/m Calculate the wave speed: v = √(T / μ) = √(200 N / 0.02 kg/m) = 100 m/s Calculate Show more…
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