00:01
All right, so we have the digestion of the weak acid.
00:02
We have a buffer solution of the weak acid and its salt.
00:06
The first question says, how many moles of acetic acid and sodium acetate are present in the solution? number of moles of the acetic acid would be the concentration times the volume in liters.
00:22
And that would give you 0 .006 moles.
00:25
Or the number of moles of the sodium acetate, the salt, is concentration times the volume, which would be 0 .0075.
00:40
The b part says, what would be when you had, when you had to add the base, strong base to it, right? you have 55 .55 mules of a 0 .092 molar solution.
00:55
So what happens is that the acetic acid will react with the strong base and then have the conjugate base and water.
01:06
Originally we had 0 .006 of this, and we had 0., the number of moles of the hydroxide, hydroxide ion added would be 0 .0005106.
01:20
And this was 0 .0075.
01:25
So all of this would react, all of the strong base would react.
01:34
And this would be added to the conjugate base of the acid...