00:01
In this question, we have been given the product quality assurance is particularly a tricky business in the dye manufacturing industry.
00:08
Okay.
00:09
Suppose the various color frequency and intensity values that comprise, they are combined into a single numerical value c, which is given in this table for a particular yellow dye.
00:22
Okay.
00:23
And during a test period in which the reactor condition are carefully controlled and the reactor is thoroughly cleaned between successive batches.
00:31
So here we have batch and the corresponding value of c.
00:34
In the first part, what we need to calculate is determine the minimum and the maximum acceptable values of c.
00:42
Okay.
00:44
So first of all, what i am going to do.
00:46
So we will try to find out what is the mean of c.
00:50
So the mean of c if you try to evaluate, so it comes out to be 73 .475.
00:56
Then if i do c minus c mean, okay, whole square.
01:03
And then i will take the addition of all of them.
01:07
So what i am going to do get, it will be 15 .3425.
01:12
So with the help of this, i have to find a standard deviation.
01:16
So i will write here my standard deviation.
01:22
Now it is given by sigma is equals to summation c minus c mean whole square.
01:28
So which is clearly divided by total number of.
01:33
Batches which is 12 here so it will be 15 .3425 divided by 12 which is coming out to be 1 .2785.
01:46
Now i will find out the minimum acceptable value it is given by sigma, c mean minus two times of sigma which is equals to 73 .475 minus two times of this 2 times of 1 .2785...