00:01
This question.
00:02
They're asked to estimate the instantaneous velocity of an arrow shot upwards and whose height is given by the function f.
00:13
And recall that view of 2 by definition equals to the limit of f of 2 plus h minus f of 2 divided by h as h goes to 0.
00:30
The expression inside the limit is called the difference quotient.
00:35
And now we will approximate the difference quotient using different values of h.
00:43
So the first step would be to calculate f of 2 plus h.
00:52
F of 2 plus h by the formula for f equals to negative 16 times 2 plus h squared plus 96 multiplied by 2 plus h.
01:12
This equals to negative 16 times 4 plus 4h plus h squared plus 192 plus 96 h.
01:31
This equals to negative 64 minus 64 h minus 16 h squared plus 192 plus 96 h.
01:47
We will also need to calculate f of 2.
01:50
To calculate the difference quotient.
01:54
F of 2 equals to negative 16 times 2 squared plus 96 times 2.
02:04
Negative 16 times 4 plus 96 times 2 equals to negative 64 plus 192.
02:16
Now we are ready to calculate the difference quotient, sorry, the difference in the numerator.
02:25
That's not difference quotient yet...