An electron enters a region of space containing a uniform 1.93 x 10^5 T magnetic field. Its speed is 193 m/s and it enters perpendicularly to the field.
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Step 1
Since the electron enters perpendicularly to the field, \( \theta = 90^\circ \) and \( \sin(90^\circ) = 1 \). Show more…
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Adi S.
An electron moving with a velocity of 26 m/s enters region A with a uniform electric field of 13 V/m that is directed opposite to the direction of motion of the electron (so the electric force is in the direction of motion). The electron travels a distance of 3 nm before exiting the region A. The velocity of the electron when it exits this region is m/s. Take the mass of the electron to be 9.1x10^(-31) kg and its charge to be 1.6x10^(-19) C. (b) The electron now enters region B with a uniform magnetic field of 8 mT perpendicular to its direction of motion. The radius of the circular path the electron would follow in this region is nm.
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