6. An object is 14cm in front of a diverging lens with a...

6. An object is 14cm in front of a diverging lens with a focal length 22cm. A converging lens with focal length 15cm is placed 15cm to the right of the diverging lens (figure below). (a) Find the position of the final image from the two lenses. (b) Find the magnification of the final image. Now the object is placed 20cm in front of the converging lens. And the diverging lens is placed 50 cm to the right of the converging lens (figure below). (c) Find the position of the final image from the two lenses. (d) Find the magnification of the final image. The focal lengths of the two lenses remain the same.

Transcript

00:01 Hello everyone today we are going to find the answer for this question so from the given two set of diagrams there are data given from that we are going to calculate the following set of question so let's start with the subdivision a so in this we are going to use the lens formula that is 1 by v minus 1 by u equal to 1 by f so we are going to find the value of v1 so we are resolving it and we are writing it as 1 by v1 1 equal to 1 by u1 minus 1 by f1 so now we are having the values we'll just substitute and find the answer 1 by 14 minus 1 by 22 so when we solve this we will get the value as 4 divided by 154 so again when we solve this we will get the v1 value as v1 is equal to 38 .5 5 so now we are going to find the v2 value.

01:02 So with the same type of formula.

01:05 So now i'm just substituting the values.

01:08 So here, 1 by v2 is equal to 1 by f minus 1 by u2.

01:20 So here the substitution will be 1 by 15 and minus 1 by u2 is nothing but 15 plus v1 that is 38 .5.

01:34 So when we solve this we will get the v2 value as v2 is equal to 20 .84.

01:45 So now we will just move on to the next subdivision that is finding on the magnification.

01:53 So the formula used here is m1 is equal to v1 by u1.

02:01 So we are having the values, we'll just substitute and find the answer.

02:05 38 .5 divided by 14.

02:08 So when we solve this we will get the m1 value.

02:11 As 2 .74.

02:16 So now we will move on in finding the m2 value.