Question

An object moves along a coordinate line with acceleration a(t) = (t + 5)^3 units per second per second. The initial velocity is 9 units per second. The velocity function is v(t) = 1/4(t+5)^4. The initial position is 6 units to the right of the origin. The position function is s(t) = .

          An object moves along a coordinate line with acceleration a(t) = (t + 5)^3 units per second per second.

The initial velocity is 9 units per second.
The velocity function is v(t) = 1/4(t+5)^4.

The initial position is 6 units to the right of the origin.
The position function is s(t) = .

An object moves along a coordinate line with acceleration a(t) = (t + 5)^3 units per second per second.

The initial velocity is 9 units per second.
The velocity function is v(t) = 1/4(t+5)^4.

The initial position is 6 units to the right of the origin.
The position function is s(t) = .

Added by Tara T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

06/18/2022

Step 1

Given acceleration function: \(a(t) = (t+5)^8\) Integrate the acceleration function to find the velocity function: \(v(t) = \int a(t) dt = \int (t+5)^8 dt\) Using the power rule of integration, we get: \(v(t) = \frac{1}{9}(t+5)^9 + C\) Show more…

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An object moves along a coordinate line with acceleration a(t) = (t+5)^3 units per second per second. The initial velocity is 9 units per second. The velocity function is v(t) = 1/4(t+5)^4 The initial position is 6 units to the right of the origin. The position function is s(t) =