Question

b. The velocity of a crate sliding down a ramp is given by $v_x = (0.75t^2)$ m/s, $v_y = (3t)$ m/s, $v_z = (1.875t^{3/2})$ m/s, where $t$ is in seconds. i. Determine the magnitude of the crate's position when $t = 2$ s. [6 marks] ii. Determine the magnitude of the crate's acceleration when $t = 2$ s. [6 marks]

          b. The velocity of a crate sliding down a ramp is given by $v_x = (0.75t^2)$ m/s, 
$v_y = (3t)$ m/s, $v_z = (1.875t^{3/2})$ m/s, where $t$ is in seconds.
i. Determine the magnitude of the crate's position when $t = 2$ s.
[6 marks]
ii. Determine the magnitude of the crate's acceleration when $t = 2$ s.
[6 marks]

b. The velocity of a crate sliding down a ramp is given by vx = (0.75t^2) m/s,
vy = (3t) m/s, vz = (1.875t^3/2) m/s, where t is in seconds.
i. Determine the magnitude of the crate's position when t = 2 s.
[6 marks]
ii. Determine the magnitude of the crate's acceleration when t = 2 s.
[6 marks]

Added by Angela A.

Engineering Mechanics: Statics and Dynamics

R. C. Hibbeler 14th Edition

Chapter 12

Instant Answer

Solved by Expert Mahendra Rathore

Step 1

To determine the magnitude of the crate's position when t = 2 s, we need to find the magnitude of the position vector. The position vector is given by r = (x, y, z), where x, y, and z are the components of the position vector. Given that vx = 0.75t^2 m/s, vy = 3t Show more…

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The velocity of a crate sliding down a ramp is given by vx = (0.75t^2) m/s, vy = (3t) m/s, vz = (1.875t^(3/2)) m/s, where t is in seconds. 1. Determine the magnitude of the crate's position when t = 2 s. [6 marks] 11. Determine the magnitude of the crate's acceleration when t = 2 s. [6 marks]