Question

\( \begin{array}{l}\Delta_{\mathrm{r}} H_{m}^{\theta}=5.06 \\ \Delta_{\mathrm{r}} G_{m}^{\theta}=-9174 \\ \Delta \mathrm{S}= \\ \Delta_{\mathrm{r}} S_{m}^{\theta}=47.7\end{array} \)

          \( \begin{array}{l}\Delta_{\mathrm{r}} H_{m}^{\theta}=5.06 \\ \Delta_{\mathrm{r}} G_{m}^{\theta}=-9174 \\ \Delta \mathrm{S}= \\ \Delta_{\mathrm{r}} S_{m}^{\theta}=47.7\end{array} \)

Δr Hm^θ=5.06
Δr Gm^θ=-9174
ΔS=
Δr Sm^θ=47.7

Added by Alejandra D.

Applied Physics

Dale Ewen, Neill Schurter, Erik… 11th Edition

Chapter 20

Instant Answer

Solved by Expert Ben Blakesley

Step 1

We have the standard enthalpy change of reaction (\(\Delta_{\mathrm{r}} H_{m}^{\theta}\)) given as 5.06 kJ/mol, the standard Gibbs free energy change of reaction (\(\Delta_{\mathrm{r}} G_{m}^{\theta}\)) as -9174 J/mol (or -9.174 kJ/mol for consistency in units), Show more…

Show all steps

Thanks for your feedback!

\( \begin{array}{l}\Delta_{\mathrm{r}} H_{m}^{\theta}=5.06 \\ \Delta_{\mathrm{r}} G_{m}^{\theta}=-9174 \\ \Delta \mathrm{S}= \\ \Delta_{\mathrm{r}} S_{m}^{\theta}=47.7\end{array} \)