00:01
In this question, it is given the rotational constant for cos and we have to calculate, we have to calculate the bond length of co and cs in ocs.
00:10
So fast to calculate a co bond let, the reduced max of the reduced mass can be calculated by using formula, mu is equal to m1m2 divided by m1 plus m2.
00:21
So for reduce mass of co will be equals to 12b into 16 divided by 12 plus 16 which is equal to 6 .86 into a minus 3 kg now movement of inertia i use use the formula i is equals to 8 h by 8 pi square bc so here h is equal to 6 .6 to 6 to 6 to 6 to 6 to 6 to minus 34 jule second c is the speed of light which is 3 to 10 to 10 centimeter b is the rotational constraint which is given 601 .5 mhz which is equals to 0 .20288 centimeters inverse now putting all the values we can calculate the value of i which is which is going to be 0 .138 into 10 to the minus 44 kg meter square.
01:05
Now the bond length formula, mu square is equal to i by mu, which is equal to put the value of i and mu, we will get mu square is equal to 0 .2 in 10 to the power minus 42.
01:16
Then mu is equal to root 2 under the bond length of co will be equals to root under up 0 .2 in 10 to a minus 42, which is 0 .44 in 10 to 1 .25 meter.
01:27
Which is equal to 0 .44 in 12 minus 11 and strong.
01:31
So, bond length of co is 4 .4 in 10 to 12 armstrong.
01:35
Now to calculate a bond length of co similarly, we have to calculate reduce mass, movement of inertia, then we have to put the value...