calculate the concentration of oxalic acid acid in g.dm^-3 when titrated with sodium hydroxide
Added by Mihlali M.
Step 1
First, we need to know the balanced chemical equation for the reaction between oxalic acid and sodium hydroxide. The equation is: H2C2O4 (aq) + 2 NaOH (aq) → Na2C2O4 (aq) + 2 H2O (l) Show more…
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What is the molarity of a solution made by dissolving $0.583 \mathrm{g}$ of the diprotic acid oxalic acid, $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},$ in enough water to make $1.75 \mathrm{L}$ of solution?
Oxalic acid dihydrate is a solid, diprotic acid that can be used in the laboratory as a primary standard. Its formula is $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O} \cdot \mathrm{A}$ student dissolves $0.750 \mathrm{grams}$ of $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$ $2 \mathrm{H}_{2} \mathrm{O}$ in water and titrates the resulting solution with a solution of sodium hydroxide of unknown concentration. If $28.0 \mathrm{mL}$ of the sodium hydroxide solution are required to neutralize the acid, what is the molarity of the sodium hydroxide solution?
You have a mixture of oxalic acid, $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},$ and another solid that does not react with sodium hydroxide. If 29.58 mL of $0.550 \mathrm{M} \mathrm{NaOH}$ is required to titrate the oxalic acid in the $4.554-\mathrm{g}$ sample to the second equivalence point, what is the mass percent of oxalic acid in the mixture? Oxalic acid and NaOH react according to the equation $$\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(\mathrm{aq})+2 \mathrm{NaOH}(\mathrm{aq}) \rightarrow \mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\ell)$$
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