calculate the energy j of the photon emitted when an electron in the hydrogen atom falls from n6

Name: calculate the energy j of the photon emitted when an electron in the hydrogen atom falls from n6 to n2 use 2178 x 10 18 j for the constant in the bohr equation answer should be in scientific notation
Uploaded: 2023-09-07T13:47:28-08:00
Duration: 1 min 32 s
Channel: Ankur S
Description: calculate the energy j of the photon emitted when an electron in the hydrogen atom falls from n6 to n2 use 2178 x 10 18 j for the constant in the bohr equation answer should be in scientific notation

Question

Ankur S · Accepted Answer

First, we need to use the Bohr equation to calculate the energy difference between the two energ

Question

Calculate the energy (J) of the photon emitted when an electron in the hydrogen atom falls from n=6 to n=2 . Use 2.178 x 10-18 J for the constant in the Bohr equation. Answer should be in scientific notation to 4 significant figures, e.g. 3000. = 3E3

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