Calculate the volume in milliliters of a 3.83 M sodium nitrate solution that contains 125. g of sodium nitrate (NaNO3). Be sure your answer has the correct number of significant digits.
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Given: Mass of sodium nitrate = 125 g Molar mass of sodium nitrate = 85.0 g/mol Number of moles = Mass / Molar mass Number of moles = 125 g / 85.0 g/mol Number of moles = 1.47 mol Show more…
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