Question

Chapter-46 Number Games What should come in place of \( \# \) in the series. (i) \( 666 / 6 / 3=\# \) a. 37 b. 333 c. 111 d. 84 (ii) \( 2,3,6, \#, 108,1944,209952 \) a. 32 b. 18 c. 12 d. 9 If A runs faster than B but not as fast as \( C \) and \( C \) runs faster than \( B \) but not as fast as \( D \), the person who runs the fastest is: a. \( A \) b. B c. C d. D Complete the square

          Chapter-46
Number Games

What should come in place of \( \# \) in the series.
(i) \( 666 / 6 / 3=\# \)
a. 37
b. 333
c. 111
d. 84
(ii) \( 2,3,6, \#, 108,1944,209952 \)
a. 32
b. 18
c. 12
d. 9

If A runs faster than B but not as fast as \( C \) and \( C \) runs faster than \( B \) but not as fast as \( D \), the person who runs the fastest is:
a. \( A \)
b. B
c. C
d. D
Complete the square

Chapter-46
Number Games

What should come in place of # in the series.
(i) 666 / 6 / 3=#
a. 37
b. 333
c. 111
d. 84
(ii) 2,3,6, #, 108,1944,209952
a. 32
b. 18
c. 12
d. 9

If A runs faster than B but not as fast as C and C runs faster than B but not as fast as D, the person who runs the fastest is:
a. A
b. B
c. C
d. D
Complete the square

Added by Christopher B.

43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Physics

Disha Experts 16th Edition

Chapter 27

Instant Answer

Solved by Expert Aakash Goyal

10/03/2021

Step 1

So, we divide 666 by 6 to get 111. Then we divide 111 by 3 to get 37. So, the answer is a. 37. (ii) The pattern in the series is that each number is multiplied by the next prime number. So, 2 is multiplied by 2 to get 4, 3 is multiplied by 2 to get 6, 6 is Show more…

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