Question

Compute $\int_{\gamma} \frac{e^z}{z^2(z^2 - 9)} dz$ for $\gamma = e^{it}$ and $0 \le t \le 2\pi$.

Name: Compute ∫γ(e^z)/(z^2(z^2 - 9)) dz for γ = e^it and 0 ≤ t ≤ 2π.
Uploaded: 2022-03-03T18:43:31-08:00
Duration: 1 min 9 s
Channel: Suchitra K
Description: Compute ∫γ(e^z)/(z^2(z^2 - 9)) dz for γ = e^it and 0 ≤ t ≤ 2π.

          Compute $\int_{\gamma} \frac{e^z}{z^2(z^2 - 9)} dz$ for $\gamma = e^{it}$ and $0 \le t \le 2\pi$.

Added by Steven A.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Suchitra K

03/03/2022

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Compute int_(gamma ) (e^(z))/(z^(2)(z^(2)-9))dz for gamma =e^(it) and 0<=t<=2pi Compute dz for y= eit and 0< t < 2T.

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Compute $\int_{\gamma} \frac{e^z}{z^2(z^2 - 9)} dz$ for $\gamma = e^{it}$ and $0 \le t \le 2\pi$.

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