Consider a swimming pool that is 50.00 m long and 25.0 m wide,If water is pumped out at a rate of 5.2 L per second, how long will it take (in hours) to lower the water level by 25 cm, as shown below?
Added by Sydnee J.
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25 m). The volume \( V \) of water to be removed is given by the formula: \[ V = \text{length} \times \text{width} \times \text{height} \] Given: - Length \( l = 50.00 \) m - Width \( w = 25.0 \) m - Height \( h = 0.25 \) m \[ V = 50.00 \, \text{m} \times 25.0 Show more…
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The level of water in an Olympic-size swimming pool $(50.0 \mathrm{m} \text { long, } 25.0 \mathrm{m} \text { wide, and about } 2 \mathrm{m}$ deep ) needs to be lowered $3.0 \mathrm{cm} .$ If water is pumped out at a rate of $5.2 \mathrm{L}$ per second, how long will it take to lower the water level $3.0 \mathrm{cm} ?$
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