Consider a metabolic reaction whereby the formation of a product has a free energy change of +15 kJ/mol. Why does this reaction proceed forward when it is coupled to the hydrolysis of ATP? Select one: a. ATP ? ADP + Pi has a large negative free energy change b. ADP + Pi ? ATP has a large negative free energy change c. ATP provides the kinetic energy for the reaction d. Release of inorganic phosphate pulls the equilibrium to the left
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In glycolysis, the reaction catalyzed by aldolase is favoured in the forward direction, even though is endergonic and freely reversible. a. Identify the reaction number and free energy (ΔG°') for this reaction. b. Explain why this reaction is forward favoured, despite being endergonic.
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For the hydrolysis of atp to adp + i, the free energy change is -7.3 kcal/mol under standard conditions (1 m concentration of both reactants and products). in the cellular environment, however, the free energy change is about -13 kcal/mol. what can we conclude about the free energy change for the formation of atp from adp and i under cellular conditions?
In the metabolism of glucose, the first step is the conversion of glucose to glucose 6 -phosphate: $$ \begin{array}{r} \text { glucose }+\mathrm{H}_{3} \mathrm{PO}_{4} \longrightarrow \text { glucose } 6 \text { -phosphate }+\mathrm{H}_{2} \mathrm{O} \\ \Delta G^{\circ}=13.4 \mathrm{kJ} / \mathrm{mol} \end{array} $$ Because $\Delta G^{\circ}$ is positive, this reaction does not favor the formation of products. Show how this reaction can be made to proceed by coupling it with the hydrolysis of ATP. Write an equation for the coupled reaction, and estimate the equilibrium constant for the coupled process.
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