Question

Consider the equation below. f(x) = x^4 - 32x^2 + 6 (a) Find the interval on which f is increasing. (Enter your answer in interval notation.) (-4, 0) U (4, ?) Find the interval on which f is decreasing. (Enter your answer in interval notation.) (-?, -4) U (0, 4) (b) Find the local minimum and maximum values of f. local minimum -250 local maximum 6 (c) Find the inflection points. (x, y) = (-4/?3, -149.28) (smaller x-value) (x, y) = (4/?3, -1250/9) (larger x-value)

          Consider the equation below.
f(x) = x^4 - 32x^2 + 6
(a) Find the interval on which f is increasing. (Enter your answer in interval notation.)
(-4, 0) U (4, ?)
Find the interval on which f is decreasing. (Enter your answer in interval notation.)
(-?, -4) U (0, 4)
(b) Find the local minimum and maximum values of f.
local minimum -250
local maximum 6
(c) Find the inflection points.
(x, y) = (-4/?3, -149.28) (smaller x-value)
(x, y) = (4/?3, -1250/9) (larger x-value)

Consider the equation below.
f(x) = x^4 - 32x^2 + 6
(a) Find the interval on which f is increasing. (Enter your answer in interval notation.)
(-4, 0) U (4, ?)
Find the interval on which f is decreasing. (Enter your answer in interval notation.)
(-?, -4) U (0, 4)
(b) Find the local minimum and maximum values of f.
local minimum -250
local maximum 6
(c) Find the inflection points.
(x, y) = (-4/?3, -149.28) (smaller x-value)
(x, y) = (4/?3, -1250/9) (larger x-value)

Added by Claudia G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vishal Parmar

04/19/2022

Step 1

Step 1: Find the inflection points by setting the second derivative equal to zero and solving for x. Show more…

Show all steps

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Consider the equation below. f(x) = x^4 - 32x^2 + 6 (a) Find the interval on which f is increasing. (Enter your answer in interval notation.) (-4, 0) U (4, infinity) Find the interval on which f is decreasing. (Enter your answer in interval notation.) (-infinity, -4) U (0, 4) (b) Find the local minimum and maximum values of f. local minimum -250 local maximum 6 (c) Find the inflection points. (x, y) = (-4/sqrt(3), -149.28) (smaller x-value) (x, y) = (4/sqrt(3), -1250/9) (larger x-value)