Consider the following initial-value problem. dy/dt - y = 1, y(0) = 0 Find L{f(t)} for f(t) = 1. (Write your answer as a function of s.) L(f(t)) = 1/s Use the Laplace transform to solve the given initial-value problem. y(t) = e^t - 1
Added by Lori B.
Close
Step 1
First, we need to take the Laplace transform of the differential equation: ℒ{dy/dt - y = 1} = sY(s) - y(0) - Y(s) = 1/s Simplifying this expression, we get: sY(s) - Y(s) = 1/s Y(s) (s - 1) = 1/s Y(s) = 1/(s(s-1)) Now, we need to take the inverse Laplace Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 91 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Verify that the function $f(t)=2 e^{-t}+t-1$ is a solution of the initial-value problem $y^{\prime}=t-y, y(0)=1 .$ [This is the function shown in Fig. $4(\mathrm{c}) .$ In Section $10.3,$ you will learn how to derive this solution.]
Differential Equations
Solutions of Differential Equations
Solve the following initial value problem: t(dy/dt) + 9y = 5t with y(1) = 8. (Find y as a function of t.) y = ?
Madhur L.
Use the Laplace transform to solve the given initial-value problem. $$\frac{d y}{d t}-y=1, \quad y(0)=0$$
The Laplace Transform
Inverse Transforms and Transforms of Derivatives
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD