00:01
Okay, this question is more related to the gaussian elimination, right? so the first equation is, sorry, the first matrix is an sort of an elementary operation.
00:15
So let's first calculate ea, so you can, i mean, simply multiply all this element, and you will, in the end, see this, d minus, 3a, e, sorry, row plus, okay, b minus, sorry, e minus 3b, and f minus 3, g, h, k.
01:05
So now if you compare the ea and a, you will find that the ea here is you multiply the first row by minus 3 and plus added to the second row.
01:23
This is a type 3 elementary operation.
01:29
And the second consider the matrix, new matrix e and compute ea.
01:41
So you compute ea you will get a, b, c, one -fose d, one -fourth e and one -fourth f -g.
01:56
Now this is quite straightforward, which is you multiply one fourth to the second row.
02:06
And this is the type 2 elementary operation.
02:15
So c, can you think of 3x3 metrics e such that ea is obtained from a by swapping the last two roles? by swapping, we should have ea equals to a, b, c, g, g -h -k -d -e -f...