Question

Consider the nucleophilic addition reaction of pentan-2-one with excess butyl magnesiumbromide, made in situ by reacting 1-bromobutane with metallic magnesium, to make 4-methyloctan-4-ol. Mg pentan-2-one 1-bromobutane 4-methyloctan-4-ol pentan-2-one d = 0.81 g/mL 1-bromobutane d = 1.27 g/mL 4-methyloctan-4-ol d = 0.82 g/mL A reaction was performed in which 0.45 mL of pentan-2-one was reacted with an excess of butyl magnesiumbromide to make 0.40 g of 4-methyloctan-4-ol. Calculate the theoretical yield and percent yield for this reaction. Theoretical yield: g Percent yield: %

          Consider the nucleophilic addition reaction of pentan-2-one with excess butyl magnesiumbromide, made in situ by reacting 1-bromobutane with metallic magnesium, to make 4-methyloctan-4-ol. Mg pentan-2-one 1-bromobutane 4-methyloctan-4-ol pentan-2-one d = 0.81 g/mL 1-bromobutane d = 1.27 g/mL 4-methyloctan-4-ol d = 0.82 g/mL A reaction was performed in which 0.45 mL of pentan-2-one was reacted with an excess of butyl magnesiumbromide to make 0.40 g of 4-methyloctan-4-ol. Calculate the theoretical yield and percent yield for this reaction. Theoretical yield: g Percent yield: %

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Consider the nucleophilic addition reaction of pentan-2-one with excess butyl magnesiumbromide, made in situ by reacting 1-bromobutane with metallic magnesium, to make 4-methyloctan-4-ol. Mg pentan-2-one 1-bromobutane 4-methyloctan-4-ol pentan-2-one d = 0.81 g/mL 1-bromobutane d = 1.27 g/mL 4-methyloctan-4-ol d = 0.82 g/mL A reaction was performed in which 0.45 mL of pentan-2-one was reacted with an excess of butyl magnesiumbromide to make 0.40 g of 4-methyloctan-4-ol. Calculate the theoretical yield and percent yield for this reaction. Theoretical yield: g Percent yield: %

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Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Snehal J

03/22/2022

Step 1

Given: - Mass of pentan-2-one = 0.3645 g - Molar mass of pentan-2-one = 86.134 g/mol - Molar mass of 4-methyloctan-4-ol = 144 g/mol Number of moles of pentan-2-one = 0.3645 g / 86.134 g/mol = 0.004225 mol Theoretical yield of 4-methyloctan-4-ol = 0.004225 mol * Show more…

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Consider the nucleophilic addition reaction of pentan-2-one with excess butyl magnesiumbromide, made in situ by reacting 1-bromobutane with metallic magnesium, to make 4-methyloctan-4-ol. pentan-2-one d = 0.81 g/mL 1-bromobutane d = 1.27 g/mL 4-methyloctan-4-ol d = 0.82 g/mL A reaction was performed in which 0.45 mL of pentan-2-one was reacted with an excess of butyl magnesiumbromide to make 0.40 g of 4-methyloctan-4-ol. Calculate the theoretical yield and percent yield for this reaction. Theoretical yield: Percent yield:

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