00:01
Hello everyone so this is the question that we have 7 .2 % students in the age bracket of 12 to 18 were bullied in the six months with sixth grade being the highest percentage at 13 .9 % and 12th grade was at the lowest bullet percentage which was 2 .3 percentage so now a data was taken of private and public school so here is the private school and here is the public school now this is the sample size and this is the number bullied so in private the sample size was 215 bullied were 14 and in public sample size was to 215 and bully 221.
01:09
So we need to find the hypothesis and claim the correct hypothesis.
01:17
Correct hypothesis.
01:20
First part and second part, we need to find the p value of the data.
01:26
So let's jump on to the solution of the question.
01:29
So this is all given to us.
01:32
Let us say sample number one.
01:35
Sample 1, which is of private.
01:40
So right.
01:41
Now x is 14 that is the number of events.
01:47
Samples size n is equal to 215.
01:52
So the sample proportion would be given by p1 cap is equal to x1 divided by n which is going to be 14 divided by 215 which is nothing but 0 .06 5.
02:14
Now for sample two for sample two which is public school so in public school x is equal to 21 and n is equal to two and five so my sample proportion is gonna be b two cap which is gonna be x2 divided by n2 so this is gonna be 21 divided by 215 which is nothing but 0 .0974 now, we have to give the total sample proportion.
02:50
So sample proportion is going to be given by the formula p -cap is equal to n1 p -1 cap plus n2 -cap divided by n1 plus n2.
03:08
So after putting in the values, i would get n1 is 215.
03:15
P1 cap is 0 .615 plus n2 is 215.
03:29
Multiplied by 0 .0974 divided by 215 plus 215...