The auxiliary roots of the following differential equation y'' + y' - 6y = 0 are ?? = ?? = -2 ?? = 2 and ?? = -3 ?? = 1 - 2i and ?? = 1 + 2i ?? = (3 - ?29)/2 and ?? = (3 + ?29)/2
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First, we have a second-order linear homogeneous differential equation with constant coefficients: $$y'' + y' - 6y = 0$$ We are given the auxiliary roots: Show more…
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