Question

Determine by how much phase angle v1(t) leads i1(t), where v1(t)=4 sin (377t+27°) V i1(t)=0.05 cos (377t-24°) A Notes on entering solution: * Enter your solution with respect to "v leads i by" * Enter your solution in degree * Do not include units in your answer * Make sure your final answer is between -180deg and 180deg * ex. 5° is entered as 5

          Determine by how much phase angle v1(t) leads i1(t),
where

v1(t)=4 sin (377t+27°) V

i1(t)=0.05 cos (377t-24°) A

Notes on entering solution:

* Enter your solution with respect to "v leads i by"
* Enter your solution in degree
* Do not include units in your answer
* Make sure your final answer is between -180deg and 180deg
* ex. 5° is entered as 5

Determine by how much phase angle v1(t) leads i1(t),
where

v1(t)=4 sin (377t+27°) V

i1(t)=0.05 cos (377t-24°) A

Notes on entering solution:

* Enter your solution with respect to "v leads i by"
* Enter your solution in degree
* Do not include units in your answer
* Make sure your final answer is between -180deg and 180deg
* ex. 5° is entered as 5

Added by Ydjsjsj S.

Basic Engineering Circuit Analysis

J. David Irwin, Robert M. Nelms 11th Edition

Chapter 8

Instant Answer

Solved by Expert Keondre Parker

04/02/2024

Step 1

The given expressions are: \[ v_1(t) = 4 \sin(377t + 27^\circ) \, V \] \[ i_1(t) = 0.05 \cos(377t - 24^\circ) \, A \] Since \(\sin(x) = \cos(x - 90^\circ)\), we can convert \(v_1(t)\) from sine to cosine to match \(i_1(t)\): \[ v_1(t) = 4 \cos(377t + 27^\circ - Show more…

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