Question

Determine the critical points of the function (1) 78:31 \[ f(x)=\left\{\begin{array}{ll} x^{3}+6 x^{2} & \text { if } x \leq 0 \\ x^{2}-4 x & \text { if } x>0 \end{array}\right. \] in the interval $ [-7,7] $.

          Determine the critical points of the function
(1) 78:31
\[
f(x)=\left\{\begin{array}{ll}
x^{3}+6 x^{2} & \text { if } x \leq 0 \\
x^{2}-4 x & \text { if } x>0
\end{array}\right.
\]
in the interval \( [-7,7] \).

$Determine the critical points of the function (1) 78:31 f(x)={ x^3+6 x^2 if x ≤ 0 x^2-4 x if x>0 . in the interval [-7,7].$

Added by Lori V.

Calculus for Scientists and Engineers: Early Transcendental

William Briggs, Lyle Cochran, Bernard… 1st Edition

Chapter 4

Instant Answer

Solved by Expert Aparna Shakti

Step 1

The function is defined as: \[ f(x) = \begin{cases} x^3 + 6x^2 & \text{if } x \leq 0 \\ x^2 - 4x & \text{if } x > 0 \end{cases} \] Show more…

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Determine the critical points of the function (1) 78:31 \[ f(x)=\left\{\begin{array}{ll} x^{3}+6 x^{2} & \text { if } x \leq 0 \\ x^{2}-4 x & \text { if } x>0 \end{array}\right. \] in the interval $ [-7,7] $.