00:01
Hi, in this question we have been given vertices of a triangle as a point has vertices of 1, minus 2, 1.
00:13
Then second vertex is having coordinate of 0, 3, 2 and c is minus 2, 1, minus 1 and then so first of all we need to find the midpoint of these vertices of triangle and then we will find the perimeter.
00:35
So here let us draw this triangle.
00:38
So this is let us consider a triangle.
00:42
Here we have b coordinate that is 0, 3, 2 and this is a, 1, minus 2, 1 and this is c which is having minus 2, minus 1 and 3.
00:56
So this point will be vertices of ec, this point will be vertices of av and this is midpoint of vertices ac.
01:07
Let us name this as p, q and r.
01:11
So midpoint is given by x1 plus x2 divided by 2, y1 plus y2 divided by and z1 plus z2 divided by 2.
01:29
So we will be using this formula to find the midpoint of each vertices.
01:34
So first of all we will calculate midpoint of av.
01:42
So this is p and its coordinate will be 0 plus 1 divided by 2, then 3 minus 2 divided by 2, then 2 plus 1 divided by 2.
01:56
So on solving this we will get the coordinate of p as 1 divided by 2, 1 divided by 2 and this is 3 divided by 2.
02:06
Similarly we will find the midpoint of bc.
02:15
So this is q and here we will have 0 minus 2 divided by 2, then 3 minus 1 divided by 2, then 2 plus 3 divided by 2.
02:29
So this is q and its coordinate will be now minus 1, 1 and 5 divided by 2.
02:36
So in similar way midpoint of ac that is r, coordinate will be minus 2 plus 1 divided by 2, then minus 1 minus 2 divided by 2, then it's 3 plus 1 divided by 2.
02:58
So this will be minus 1 divided by 2, then minus 3 divided by 2 and then 2.
03:05
So we have calculated the coordinate of p, q and r...