Determine the radius of convergence for the series below. $$ \sum_{n=0}^{\infty} \frac{z^{2n+15}}{(n+4)!} $$ Provide your answer below.
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The series is given by: $$ \sum_{n=0}^{\infty} a_n = \sum_{n=0}^{\infty} \frac{z^{2n+15}}{(n+4)!} $$ Here, the general term is $a_n = \frac{z^{2n+15}}{(n+4)!}$. Show more…
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