00:01
In this problem, we want to determine if this series is convergent by expressing the partial sum s of n as a telescoping sum, and then we will find this sum.
00:11
Now, first thing you have to do is to rewrite our series.
00:14
Note that this is equivalent to 6 times the summation from n equal to 2 to infinity of 1 over n squared minus 1.
00:24
And then we will rewrite 1 over n squared minus 1 into its partial fractions.
00:30
We note that 1 over n squared minus 1 is equal to 1 over n minus 1 times n plus 1.
00:40
So we will have partial fractions with denominators n minus 1 and n plus 1.
00:46
And then the numerators will be constants.
00:49
That's called them a and b.
00:51
So if i'm going to multiply this by the, denominator n squared minus 1, then i'm going to have 1 equal to a times n plus 1 plus b times n minus 1.
01:05
So if our n minus 1 equals 0, this gives us n equal to 1, and our equation now becomes 1 equal to a times 1 plus 1, that's going to be a equal to 1ā2.
01:24
And if n plus 1 equals 0, it means n equals negative 1, then you will have 1 that's equal to b times negative 2.
01:40
That's going to give us b equal to negative 1 half.
01:44
So our 1 over n squared minus 1 is actually equal to 1 half over n minus 1 ,000, minus 1 ,000, we have one half over n plus 1...