Question

Differentiate. \(y = \frac{8}{4 - 5x^2}\) \(\frac{dy}{dx} = \square\) 

          Differentiate.
\(y = \frac{8}{4 - 5x^2}\)
\(\frac{dy}{dx} = \square\)
Differentiate. y = (8)/(4 - 5x^2) (dy)/(dx) = □

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Differentiate. y=(8)/(4-5x^(2)) (dy)/(dx)= Differentiate 8 y= 4-5x2 Kp dx
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Transcript

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00:01 Let's have a look at the question.
00:02 So the question state that differentiate the following function and we have y is equals to x to the power 8 and e to the power x.
00:14 So here let us take that this is the first equation.
00:18 So now on differentiating the equation 1 both side with respect to x we will get dy by dx is equals to d by dx of x to the power 8 and e to the power x.
00:56 So now we know that the differentiation of any term which has u v form.
01:04 So we will write it as u then differentiation of v with respect to x and plus here we will write v and differentiation of u with respect to x.
01:16 So same applying here in our question we will get x 8 d by dx of e to the power x and added with e to the power x and d by dx of x to the power 8.
01:33 So now here we will get x to the power 8 multiplied with e to the power x and added with e to the power x multiplied with 8x to the power 7...
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