(e) A square threaded bolt of root diameter \( 22.5 \mathrm{~mm} \) and pitth \( 5 \mathrm{~mm} \) is tightened by screwing a nut. whose mean diameter of bearing surface is \( 50 \mathrm{~mm} \) If the co.efficient of friction for the nut and bolt is 0.1 and for the nut and the bearing surface is 0.16 . Find the force required at the end of the spanner \( 500 \mathrm{mmm} \) long when the load on the bolt is \( 10 \mathrm{KN} \). \[ \tan \theta=\mu \]
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- Given: root (minor) diameter = 22.5 mm, pitch = 5 mm ⇒ mean thread diameter d_m = root + p/2 = 22.5 + 2.5 = 25.0 mm = 0.025 m. - Lead = 5 mm. Lead angle tanλ = lead/(π d_m) = 5/(π·25) = 0.063662. - Friction coefficient on threads μ = 0.10. Use screw torque Show more…
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