Question

Evaluate f(x) at x = -1, 6, and 4. $\begin{aligned} f(x) = \begin{cases} x^2 + 4x + 5 & \text{if } -1 \le x < 3\\ x + 5 & \text{if } 3 \le x < 5\\ x^3 + 3 & \text{if } 5 \le x \le 10 \end{cases} \end{aligned}$ Evaluate f(x) at x = -1. f(-1) =

          Evaluate f(x) at x = -1, 6, and 4.
$\begin{aligned} f(x) = \begin{cases} x^2 + 4x + 5 & \text{if } -1 \le x < 3\\ x + 5 & \text{if } 3 \le x < 5\\ x^3 + 3 & \text{if } 5 \le x \le 10 \end{cases} \end{aligned}$
Evaluate f(x) at x = -1.
f(-1) =

Evaluate f(x) at x = -1, 6, and 4.
f(x) = x^2 + 4x + 5 if -1 ≤ x < 3
x + 5 if 3 ≤ x < 5
x^3 + 3 if 5 ≤ x ≤ 10
Evaluate f(x) at x = -1.
f(-1) =

Added by Erica J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Charles Carter

05/05/2020

Step 1

To evaluate f(x) at x = -1, we substitute -1 into the function f(x) = x² + 4x + 5. f(-1) = (-1)² + 4(-1) + 5 = 1 - 4 + 5 = 2 Show more…

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Evaluate f(x) at x = -1, 6, and 4. f(x) = x² + 4x+5 if - 1 Evaluate f(xatx=-1,6,and4 +4x+5if-1x<3 f(x)= x+5if3x<5 x3+3if 5x10 Evaluate f(xatx=-1. f-1=