Evaluate \( \int \frac{1}{\sqrt{4+x^{2}}} d x \)
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The general form of the integral that relates to the inverse tangent is \( \int \frac{1}{a^2 + x^2} dx = \frac{1}{a} \tan^{-1}(\frac{x}{a}) + C \), where \(a\) is a constant and \(C\) is the constant of integration. Show more…
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