Evaluate the following integral.\\ $\int \frac{96x^2}{x^4 - 50x^2 + 49} dx$
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Let $$ \frac{96x^2}{(x-7)(x+7)(x-1)(x+1)} = \frac{A}{x-7} + \frac{B}{x+7} + \frac{C}{x-1} + \frac{D}{x+1} $$ Multiplying both sides by $(x-7)(x+7)(x-1)(x+1)$, we get Show more…
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