1. Evaluate the following integrals: a. $int_1^2 (ln x)^2 , dx$ b. $int an^4 x sec^6 x , dx$ c. $int x sqrt{25 - x^2} , dx$ d. $int frac{1}{x^2 sqrt{x^2 - 1}} , dx$ e. $int frac{dx}{(x-3)(x^2+1)}$
Added by David L.
Close
Step 1
Use integration by parts with u = (ln x)^2, dv = dx. Then du = (2 ln x)/x dx and v = x. So I = [x (ln x)^2]_1^2 - ā«_1^2 x * (2 ln x)/x dx = [x (ln x)^2]_1^2 - 2 ā«_1^2 ln x dx. Show moreā¦
Show all steps
Your feedback will help us improve your experience
Drew Scalzo and 65 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the following integrals: a. ā«ā² (ln x)² dx b. ā« tanā“x secā¶x dx c. ā« xā(25 - x²) dx d. ā« 1 / [x²ā(x² - 1)] dx e. ā« dx / [(x - 3)(x² + 1)]
Adi S.
Evaluate the following definite and indefinite integrals: 1. ā« xā(x+4) dx 2. ā« x cos(3x²) dx 3. ā« 3x²(x³-2)ā“ dx 4. ā« sec² x tan² x dx 5. ā« wā(w²+6) dw 6. ā«āā² (5xā“+1) dx 7. ā«ā¹ (2x+1)ā“ dx 8. ā«āāā“ x³(xā“-2) dx
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD